Confidential Interval

Assignment: M&M support Part 3 M&Ms Project Part 3 Strayer University math 300 Statistics Professor Ahmed Rawish borderland 14, 2012 reconstruct a 95% government agency separation for the affinity of blue M&Ms candies. 95% combine detachment for residual is marry by [pic] where p = x/n = 847/4179 = 0.202680067, [pic]= 1.959963985, n = 4179 Therefore, CI is wedded by, [pic] = (0.190492031, 0.214868103) Thus with 95% corporate trust we can claim that the isotropy of blue M&Ms® candies is within (0.190492031, 0.214868103). Details | assurance separation Estimate for property | | | | | entropy |  | |Sample Size |4179 | | finalize of Successes |847 | |Confidence Level |95% | |  |  | |Intermediate Calculations | |Sample comparison |0.202680067 | |Z Value |-1.

959963985 | | model Error of the Proportion |0.0062185 | | legal separation Half Width |0.012188036 | |  |  | |Confidence detachment | |Interval destroy Limit |0.190492031 | |Interval upper berth Limit |0.214868103 | 3 pts. constitute a 95% Confidence Interval for the proportion of orangish tree M&Ms® candies. 95% Confidence Interval for proportion is given by [pic] where p = x/n = 845/4179 = 0.202201484, [pic]= 1.959963985, n = 4179 Therefore, CI is given by, [pic] =...If you neediness to get a proficient essay, inn it on our website: Orderessay

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